Mikhail Arkhangelsky - Soviet camera operator and film director. Article "Архангельский, Михаил Фёдорович" in Russian Wikipedia has 6.7 points for quality (as of November 1, 2023). The article contains 1 references and 3 sections. The article also contains quality flaw template, which reduce quality score.
Since the creation of article "Архангельский, Михаил Фёдорович", its content was written by 12 registered users of Russian Wikipedia and edited by 12 registered Wikipedia users in all languages.
The article is cited 11 times in Russian Wikipedia and cited 11 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Russian: #382207 01.2011 |
Global: #3854329 05.2018 |
| Best Rank | Russian: #78010 08.2020 |
Global: #1855417 09.2014 |
On 28 April 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: YouTube, Fallout, Facebook, Baby Reindeer, Challengers, Premier League, Fallout, deaths in 2024, Queen of Tears, Arsenal F.C..
In Russian Wikipedia the most popular articles on that day were: Яндекс, YouTube, Вход Господень в Иерусалим, ВКонтакте, Иванов, Тимур Вадимович, Фоллаут (телесериал), Банионис, Донатас Юозович, Wildberries, Россия, Сёгун (мини-сериал, 2024).
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(3.35+0.55+0+15+16.32)-0.35$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
